# Double-convex lenses are to be manufactured from a glass of refractive index 1.55, with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be 20cm?

Given Data:

Refractive index of glass, μ = 1.55

Focal length of the double-convex lens, f = 20 cm

Consider,

Radius of curvature of one face of the lens = R1

Radius of curvature of the other face of the lens = R2

Radius of curvature of the double-convex lens = R

Since it is mentioned that both faces are of the same radius,

R1 = R and R2 = -R

The value of R can be calculated as: t

… (1)

(Explanation: The above formula is generated by the ray diagram of the double convex lens. )

Substituting the given data in the equation (1), we get,

R = 0.55 × 2 × 20

R = 22 cm

Hence, the radius of curvature of the double-convex lens is 22 cm.

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