# Dihydrogen gas us

The given reaction is CO (g) + H2O (g) CO2 (g) + H2 (g)

Given: Temperature = 400° C

Partial pressure of CO (PCO) = Partial pressure of H2O (PH2O) = 4.0 bar

Kp = 10.1 bar

Formula: Kp =

Let the partial pressure of H2 (PH2) at equilibrium = P bar

By applying the formula given below:

Kp =

Where Px and PY are the partial pressures of x and y(products)

PA and PB are the partial pressures of a and b (reactants)

Hence, Kp =

As Kp = 10.1 bar (given)

10.1 =

10.1 =

By taking square roots of both the sides, we get

√10.1 =

0.3178 =

12.712– 0.3178 P = P

4.178 P = 12.712

P = 3.042 bar

Thus, the partial pressure of H2 (PH2) at equilibrium = P bar = 3.042 bar.

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