Q. 2 A4.0( 39 Votes )

# Balance the follo

Answer :

** Balanced equation:** Cu + 2H

_{2}SO

_{4}→ CuSO

_{4}+ SO

_{2}↑ + 2H

_{2}O

Step 1: Write the unbalanced equation

Cu + H_{2}SO_{4}→ CuSO_{4} + SO_{2}↑ + H_{2}O

Step 2: Compare the number of atoms of reactants with the number of atoms of products.

Step 3: Now, first we consider the element having unequal no. of atoms on both sides. Thus, first let us consider the oxygen atom. If we multiply 2 in the reactant (in H_{2}SO_{4}) and 2 in the product (in H_{2}O), we will get the equal number of oxygen atoms in both sides.

Step 4: Write the resulting equation:

Cu + 2H_{2}SO_{4}→ CuSO_{4} + SO_{2}↑ + 2H_{2}O

Step 5: Now check whether the equation is balanced or not by comparing the atoms

We find that the equation is balanced now.

Step 6: Write down the final balanced equation:

Cu + 2H_{2}SO_{4}→ CuSO_{4} + SO_{2}↑ + 2H_{2}O

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