Q. 14.1( 200 Votes )
Construct the following quadrilaterals.
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
(i) A rough sketch of the quadrilateral can be drawn to make the sum easier.
Step 1: First we will draw the base LT = 2.5 cm.
Step 2: Taking T and L as center we draw the arcs each measuring of 4 cm intersecting at point I. Join the points TI and IL.
Step 3: Now, taking L and I as center we draw the arcs measuring of 4.5 cm and 3 cm intersecting at point F. Join the points LF and FI.
Step 1: Firstly we will draw the base for our diagram , OD = 10 cm.
Step 2: Taking G as a center we draw an arc of measuring 10 cm and take D as a center we draw an arc of length 5 cm such that both are intersecting at the point L.
Join the points GL and LD.
Step 3: Taking D as a center we draw an arc of measuring 6 cm and taking L as a center we draw an arc of length 7.5 cm such that both are intersecting at the point O.
Join the points DO and LO.
Step 4: Join OG.
Step 1: Draw a line segment BN of 5.6 cm.
Step 2: Draw a perpendicular bisector of BN.
[Since diagonal of a rhombus bisect perpendicularly. ]
Step 3: Taking O as the center, draw arcs measuring 3.25 cm such that they intersect the perpendicular bisector at point D and E.
Step 4: Joining the points BD, BE, EN and DN.
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