Q. 14.1( 200 Votes )

Construct the following quadrilaterals.(i) Quadrilateral LIFTLI = 4 cmIF = 3 cmTL = 2.5 cmLF = 4.5 cmIT = 4 cm(ii) Quadrilateral GOLDOL = 7.5 cmGL = 6 cmGD = 6 cmLD = 5 cmOD = 10 cm(iii) Rhombus BENDBN = 5.6 cmDE = 6.5 cm

(i) A rough sketch of the quadrilateral can be drawn to make the sum easier.

Step 1: First we will draw the base LT = 2.5 cm.

Step 2: Taking T and L as center we draw the arcs each measuring of 4 cm intersecting at point I. Join the points TI and IL.

Step 3: Now, taking L and I as center we draw the arcs measuring of 4.5 cm and 3 cm intersecting at point F. Join the points LF and FI.

(ii) Firstly we draw a rough sketch of the sum.

Step 1: Firstly we will draw the base for our diagram , OD = 10 cm.

Step 2: Taking G as a center we draw an arc of measuring 10 cm and take D as a center we draw an arc of length 5 cm such that both are intersecting at the point L.

Join the points GL and LD.

Step 3: Taking D as a center we draw an arc of measuring 6 cm and taking L as a center we draw an arc of length 7.5 cm such that both are intersecting at the point O.

Join the points DO and LO.

Step 4: Join OG.

(iii) Firstly, we draw a rough sketch of the sum.

Step 1: Draw a line segment BN of 5.6 cm.

Step 2: Draw a perpendicular bisector of BN.

[Since diagonal of a rhombus bisect perpendicularly. ]

Step 3: Taking O as the center, draw arcs measuring 3.25 cm such that they intersect the perpendicular bisector at point D and E.

Step 4: Joining the points BD, BE, EN and DN.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Squaring Using Geometry.43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses