Q. 14.1( 200 Votes )

# Construct the following quadrilaterals.

(i) Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

Answer :

(i) A rough sketch of the quadrilateral can be drawn to make the sum easier.

Step 1: First we will draw the base LT = 2.5 cm.

Step 2: Taking T and L as center we draw the arcs each measuring of 4 cm intersecting at point I. Join the points TI and IL.

Step 3: Now, taking L and I as center we draw the arcs measuring of 4.5 cm and 3 cm intersecting at point F. Join the points LF and FI.

(ii) Firstly we draw a rough sketch of the sum.

Step 1: Firstly we will draw the base for our diagram , OD = 10 cm.

Step 2: Taking G as a center we draw an arc of measuring 10 cm and take D as a center we draw an arc of length 5 cm such that both are intersecting at the point L.

Join the points GL and LD.

Step 3: Taking D as a center we draw an arc of measuring 6 cm and taking L as a center we draw an arc of length 7.5 cm such that both are intersecting at the point O.

Join the points DO and LO.

Step 4: Join OG.

(iii) Firstly, we draw a rough sketch of the sum.

Step 1: Draw a line segment BN of 5.6 cm.

Step 2: Draw a perpendicular bisector of BN.

[Since diagonal of a rhombus bisect perpendicularly. ]

Step 3: Taking O as the center, draw arcs measuring 3.25 cm such that they intersect the perpendicular bisector at point D and E.

Step 4: Joining the points BD, BE, EN and DN.

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