Answer :

(i) Firstly we draw a rough sketch of the sum.

Step 1: First we draw the line segment AC with measurement 7.5cm

Step 2: Taking A as the center, we draw an arc of 4.5cm and taking C as a center we draw another arc such that they are intersecting.

Join AB and AC.

Step 3: Again taking A and C as a center we draw an arc of 6 cm and 7 cm respectively.

Step 4: Join AD and DC.

We get the required quadrilateral ABCD.

(ii) Firstly we draw a rough sketch of the sum.

Step 1: First we draw the line segment PU with measurement 6.5cm

Step 2: Taking P as the center, we draw an arc of 5cm and taking U as a center we draw another arc of 6.5 cm such that they are intersecting.

Step 3: Join PM and MU.

Step 3: Again taking P and U as a center we draw an arc of 4 cm and 3.5 cm respectively intersecting at J.

Step 4: Join PJ and PU.

(iii) Firstly we draw a rough sketch of the sum.

Step 1: First draw the base 0E= 7.5 cm

Step 2: Taking O as a center, we draw an arc of 4.5 cm . Again taking E as a center we draw an arc of 6 cm such that they are intersecting at point M.

Step 3: Join OM and ME.

Step 4: Taking O as a center, we draw an arc of 6 cm. Again taking E as a center we draw an arc of 4.5 cm such that they are intersecting at point R.

Step 5: Join OR and OE.

(iv) We know that all sides of a rhombus are of the same length.

Hence, BE = ES = ST = TB.

A rough diagram for the sum.

Step 1: First, we will draw the base for the diagram.

Step 2: Taking 4.5 cm each from E and T we draw the arc such that intersecting each other at the point B.

Step 3: Joining BE and BT.

Step 4: Taking 4.5 cm each from E and T we draw the arc such that intersecting each other at the point T.

Step 5: Joining ES and TS.

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