Q. 85.0( 1 Vote )

# Consider two proc

Given V1=V2

We know that,

Work done = force ×displacement

Volume = area ×displacement

Therefore,

Work done=pressure ×volume

Let change in the volume of system = ΔV = V2-V1

Pressure =P

Thus, work done by the system W

ΔW=PΔV

For process A ΔW1=P1ΔV1

For process B ΔW2=P2ΔV2

Since ΔV1=ΔV2 we can write,

P1 < P2 (from graph)

Therefore ΔW1 < ΔW2.

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