Answer :

Given V1=V2


We know that,


Work done = force ×displacement



Volume = area ×displacement


Therefore,


Work done=pressure ×volume


Let change in the volume of system = ΔV = V2-V1


Pressure =P


Thus, work done by the system W


ΔW=PΔV


For process A ΔW1=P1ΔV1


For process B ΔW2=P2ΔV2


Since ΔV1=ΔV2 we can write,




P1 < P2 (from graph)


Therefore ΔW1 < ΔW2.

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