Q. 85.0( 1 Vote )
Consider two proc
Answer :
Given 
V1=
V2
We know that,
Work done = force ×displacement
Volume = area ×displacement
Therefore,
Work done=pressure ×volume
Let change in the volume of system = ΔV = V2-V1
Pressure =P
Thus, work done by the system W
ΔW=PΔV
For process A ΔW1=P1ΔV1
For process B ΔW2=P2ΔV2
Since ΔV1=ΔV2 we can write,
P1 < P2 (from graph)
Therefore ΔW1 < ΔW2.
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