Q. 35.0( 3 Votes )

Consider the foll A. A = Conc. HCl; B = Fe; C = NH4OH; D = PbO

B. A = Conc. H2SO4; B = Fe; C = NH4OH; D = Pb(NO3)2

C. A = Conc. H2SO4; B = Fe; C = NH3; D= Pb(NO3)2

D. A = Conc. HCl; B = Fe; C = NH3; D =PbO

Answer :

Step 1: When sodium chloride reacts with conc. H2SO4, it forms hydrogen chloride (HCl) and sodium sulphate (Na2SO4).


The reaction that takes place is:


2NaCl + conc. H2SO4 2HCl + Na2SO4


Thus, A is concentrated H2SO4


Step 2: When hydrogen chloride reacts with iron metal (Fe), it forms iron (II) chloride (FeCl2) and hydrogen gas (H2).


The reaction that takes place is:


Fe + HCl FeCl2 + H2


Thus, B is Fe.


Step 3: When hydrogen chloride reacts with ammonia (NH3), it forms ammonium chloride (NH4Cl).


The reaction that takes place is:


NH3 + HCl NH4Cl


Thus, C is ammonia (NH3).


Step 4: When hydrogen chloride reacts with lead nitrate [Pb(NO3)2], it forms lead chloride (PbCl2) and nitric acid (HNO3) .


The reaction that takes place is:


Pb(NO3)2 + HCl PbCl2 + HNO3


Thus, D is lead nitrate [Pb(NO3)2]

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