Q. 274.5( 4 Votes )

Consider the fiss

Answer :

Given that,


Mass of a nucleus , m1 = 238.05079 u


Mass of a nucleus , m2 = 139.90543 u


Mass of a nucleus , m3 = 98.90594 u


Mass of a neutron , m4 = 1.008665 u


In the fission of , 10 beta particles are emitted. The nuclear reaction is,



Energy released during above nuclear fission is given by,



Where,


m’ represents the corresponding atomic masses of the nuclei


= m1 – 92me ( atomic number 92)


= m2 – 58me ( atomic number 58)


= m3 – 44me ( atomic number 44)


= m4




=


= (0.247995)u×c2


But, u = 931.5 MeV/c2


Q = 0.247995×931.5 Mev


= 231.007 MeV


The energy released during given fission reaction is 231.007 MeV.


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