# Consider the fiss

Given that,

Mass of a nucleus , m1 = 238.05079 u

Mass of a nucleus , m2 = 139.90543 u

Mass of a nucleus , m3 = 98.90594 u

Mass of a neutron , m4 = 1.008665 u

In the fission of , 10 beta particles are emitted. The nuclear reaction is,

Energy released during above nuclear fission is given by,

Where,

m’ represents the corresponding atomic masses of the nuclei

= m1 – 92me ( atomic number 92)

= m2 – 58me ( atomic number 58)

= m3 – 44me ( atomic number 44)

= m4

=

= (0.247995)u×c2

But, u = 931.5 MeV/c2

Q = 0.247995×931.5 Mev

= 231.007 MeV

The energy released during given fission reaction is 231.007 MeV.

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