# Consider the arra

To get a dark fringe at O, the path difference between the two rays coming from M and N should be .

The geometrical path difference is given by

Here, and

Therefore, to have a minimum at O,

Solving the above equation, we get,

Squaring both sides,

Ignoring as its very small in comparison with other two.

To have minimum d, n=0.

(b) Here, . The width of the dark fringe would be

.

This fringe is both above and below O. After this dark fringe would be the first bright fringe. So we divide it by two, to locate the bright fringe. Here, the location is given by x.

(c) From the above problem,

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