Answer :

The output/collector current of the amplifier circuit is given by IL=IC=β×IB , where IB is the base current and . α is the fraction of emitter current received at the collector. This means that IC=α×IE and value of is about 0.95 to 0.99. Let us put in equation of and therefore . The power gain at the output is directly proportional to β2. Putting β=99 then power gain is proportional to 992=9801 Hence the output power is several times greater than the input power. The power gain or extra power is coming from the relationship between α and β parameters.


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