Answer :

Given:


Electric field E = 3 × 103 N/C


Side of square, s = 10 cm



a) Flux of field through square whose plane is parallel to yz plane.


We understand that the normal to the plane is parallel to the direction of field.


So, θ = 0°


Φ = E . A


Φ = E × A × cos(θ) …(1)


Where, E = Electric field


A = Area through which we have to calculate flux


θ = Angle between normal to surface and the Electric field


A = s2


A = .01 m2


Plugging values, of E, A and θ in equation (1)


Φ = 3 × 103 NC-1 × 0.01m2 × cos0°


Φ = 30 Nm2C-1


b) If normal to its (square’s) plane makes 60° with the X axis.


θ = 60°


Φ = E × A × cos(θ)


Φ = 3 × 103 NC-1 × 0.01m2 × cos60°


Φ = 15 Nm2C-1


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