Answer :

Given, i0 =20 μA =20×10-6 A
And temperature, T=300K

a) Forward biasing voltage, V=300mV
According to the current diode equation,

b) Now the current has doubled, i.e. i = 4 A

According to the current diode equation,

i = i0 (eeV/kT – 1)

Taking log both sides,

V= 318mV

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