Answer :

Given, i0 =20 μA =20×10-6 A
And temperature, T=300K

a) Forward biasing voltage, V=300mV
According to the current diode equation,





b) Now the current has doubled, i.e. i = 4 A


According to the current diode equation,


i = i0 (eeV/kT – 1)





Taking log both sides,




V= 318mV


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