# Consider a non-conducting ring of radius r and mass m which has a total charge q distributed uniformly on it. The ring is rotated about its axis with an angular speed ω.(a) Find the equivalent electric current in the ring.(b) Find the magnetic moment μ of the ring.(c) Show that ℓ where ℓ is the angular momentum of the ring about its axis of rotation.

Given-
Radius of the ring = r

Mass of the ring = m

Total charge enclosed on the ring = q

(a) Angular speed-

We know that angular speed is given by- now frequency f   Current in the ring,   (b)For a ring of area A with current i flowing through it, magnetic moment, where,

A= area of cross section

i=current flowing through it

n = number of turns

for number of turns n = 1 From (1) × = (d) Angular momentum l, where

I is moment of inertia of the ring about its axis of rotation. is angular velocity Where

m is the mass

r is the radius of gyration. So, Putting this value in equation (2), we get- Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Equation of electric and magnetic field52 mins  Magnetic force on moving charge particle in magnetic field | Quiz32 mins  Magnetic force on moving charge particle in magnetic field44 mins  Magnetic field due to current carrying straight wire37 mins  Magnetic field due to current carrying circular loop36 mins  Superfast Revision of Potential & Potenial Energy (Theory + Interactive Quiz)47 mins  Few Applications of Gauss's law54 mins  Gain Confidence on Magnetic Effects of Current with Questions41 mins  Test Your Knowledge of Electric Charge & Coulomb's Law47 mins  Check your knowledge of Electric Potential | Quiz45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 