Q. 24

# Consider a certain reaction A → Products with k = 2.0 × 10^{–}^{2}s^{-}^{1}. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L^{–1}.

Answer :

Given,

k = 2.0 × 10^{–}^{2}s^{-}^{1}

time t = 100s

Concentration [A_{0}] = 1.0 mol L^{-1}

We know,

On substituting the values,

Log(1/[A]) = 2.303/2

Log[A] = -2.303/2

[A] = 0.135 mol L^{–1}

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