Answer :

Using the result n(B) + n(B’) = n(U)

n(B) + 20 = 38

n(B) = 38 – 20 = 18

We have, n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

n(A ∪ B) = 16 + 18 – 12

n(A ∪ B) = 34 – 12 = 22

Hence, n(A ∪ B) = 22.

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