Answer :
We know molar conductivity is calculated by
λ m =
λm = = 210 cm2mol-1.
λ 0HCOOH = λ0H+ + λ(HCOO-) = (349.5 + 50.5) = 400 Scm2mol-1
=
= 0.525
Or, α = 52.5%
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