Conductivity of 0

Given -

Molarity, C = 0.00241 M

Conductivity, κ = 7.896 × 10–5 S cm–1

Molar conductivity, m = ? for acetic acid = 390.5 S cm2mol–1

Molar conductivity, m = S cm2 mol-1 m = 32.76 S cm2 mol-1

To calculate the dissociation constant, Ka, we use

Ka = Equation 1

Here, we need to find the value of α (degree of dissociation), by the formula,  α = 8.4×10-2 Equation 2

Thus, substituting Equation 2 in Equation 1, we get,

Ka = = Ka = 1.86×10 - 5

The molar conductivity, m is 32.76 S cm2 mol-1 and the dissociation constant, Ka is 1.86×10-5

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