Q. 44.2( 45 Votes )
Concentration of Nitric Acid, HNO3 = 68%
Density of solution, d = 1.504 g/ml
To find: Molarity, Mo
68% of Nitric acid by mass in aqueous solution means that 68g [[68 × 100]/100] of Nitric acid present in 100g of solution.
⇒ Molecular mass of Nitric Acid, HNO3 = [1 × 1] + [1 × 14] + [16 × 3]
⇒ Number of moles of Nitric Acid = [68/63]
= 1.079 moles
⇒ Given Density, d = 1.504 g/ml
⇒ Volume, v = [100/1.504]
= 66.489 ml
⇒ Molarity, Mo = [1.079/66.489] × 1000
= 16.23 M
Therefore the molarity of the sample is 16.24 M.
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