Answer :
Given:
Temperature, T = 27° C = 300 K
Mean separation between electrons, r = 2 × 10-10 m
De-Broglie wavelength of electron is given by,
…(1)
Where,
h = Planck’s constant = 6.6 × 10-34 Js
m = mass of electron = 9.1 × 10-31 Kg
k = Boltzmann constant = 1.38 × 10-23 Jmol-1K-1
T = absolute temperature
Putting the values in equation(1), we get,
λ = 6.2 × 10-9 m
The De-Broglie wavelength is much larger than the interelectronic separation.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Calculate the de-
Physics - Board Papers(a) Plot a graph
Physics - Board PapersPlot a graph show
Physics - Board PapersAnswer the follow
NCERT - Physics Part-IIAn electron (mass
Physics - Exemplar