# Complete the following table.  From the first equation of motion,

v=u+at

here,

v = final velocity

u = initial velocity

a is the acceleration

t is the time

In the first table,

From Ist row, v = ?

v =2m/s + 4ms-2 × 3s

v = 2m/s + 12 m/s

v = 14 m/s

from 2nd row, u = ?

v = u + at

20 m/s = u + 5ms-2 × 2s

20 m/s – 10m/s = u

u = 10 m/s

Now,

In the second table, From the equation of motion,

S=ut + 1/2 at2

Where, s is the distance

“u” is the initial velocity.

“v” is the final velocity.

“t” is the time.

“a” is the acceleration

From Ist row, s = ?

S=ut + 1/2 at2

S = 5ms-1 × 3s + 1/2 × 12ms-2 × 3s × 3s

S=15m+ 54m

S = 69 m

From 2nd row, a = ?

S=ut + 1/2 at2

92m = 7ms-1 × 4s + 1/2 × a × 4s ×4s

92 m = 28 m + a × 8s2

a × 8s2 = 92 – 28 m

a × 8s2 = 64 m

a= 8 m/s2

Now, for the third table, From second equation of motion,

v2 = u2+2as

From Ist row 8 = 4 × 4 + 2 × 3 × S

8 = 16 + 6 × S

-8 = 6 × S

-8/6= S

S= -3/2 =-1.5 m

From 2nd row 10= u2+ 2× 5× 8.4

10=u2+84

-74=u2

u=-8.6m/s

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
RELATED QUESTIONS :