A) A = Benzoamide which is then reacted with Br2/KOH(Hoffman-bromimide reaction) to form aniline(B), therefore B = aniline.
B) C6H5N2+BF4- when reacted with NaNO2/Cu and heated it gives C6H5NO2(nitrobenzene) and it is reduced to aniline by Sn/HCl. Further B to C is a reaction known as carbylamine reaction. Hence, C is isocyanide benzene.
following is the overview of these reaction.
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