Complete the following chemical equations :
Z + 3 LiAiH4 → X + 3 Lif + 3AIF3
3X + 3O2 → B2 O3 + 3H2O
Z is BF3 which on reaction with a strong reducing agent like LiAlH4 gives B2H6 (X) which on oxidation yields borate.
Thus, the reactions are:
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