Answer :
Given, 6C decays to 5B.
(a) 116C → 115B + β+
So, it is β+ decay.
(b) t1/2 = 20.3 min.
λ = min-1
Ci = 0.9C˳, Cf = 0.1C˳
So,
⇒
Taking loge both sides, we get
⇒
∴
So,
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