Q. 425.0( 1 Vote )

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Answer :

(a) 21283Bi 20881Ti + 21283Bi 21284Bi + -

(b) t1/2= 1h

After 1h, 21283Bi will be half decayed

So, 21283Bi is 0.5g present

20881Ti and 21284Bi will be formed in the ratio 7/13 and total mass of the sample should be 1g. So, total mass of 20881Ti and 21284Bi is 0.5g.

Mass of 20881Ti will be ratio of mass present × total mass= And mass of 21284Bi will be of mass present × total mass= Rate this question :

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