Answer :

(a) 21283Bi 20881Ti +

21283Bi 21284Bi + -

(b) t1/2= 1h

After 1h, 21283Bi will be half decayed

So, 21283Bi is 0.5g present

20881Ti and 21284Bi will be formed in the ratio 7/13 and total mass of the sample should be 1g. So, total mass of 20881Ti and 21284Bi is 0.5g.

Mass of 20881Ti will be ratio of mass present × total mass=

And mass of 21284Bi will be of mass present × total mass=

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Calculate the eneHC Verma - Concepts of Physics Part 2

A nuclide 1 is saPhysics - Exemplar

The mass of a H-aPhysics - Exemplar

Are the nucleons Physics - Exemplar

In pair annihilatPhysics - Exemplar

The binding energPhysics - Exemplar

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Calculate the maxHC Verma - Concepts of Physics Part 2