Q. 8

Calculate the time required to heat 20 kg of water from 10°C to 35°C using an immersion heater rated 1000 W. Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200 J kg–1 K–1.

Answer :

Given:


heat capacity of water = 4200 J kg–1 K–1.


Formula used:


ΔQ=MCΔT


ΔQ=heat exchange


ΔT=tempeature change


M=mass


C=heat capacity


Heat given by heater = heat taken by water


0.8× 1000× t=20× 4200× (35-10)


t=2625 s=43.75 minutes


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