Q. 84.3( 27 Votes )
Calculate the ‘sp
Given, Z=atomic number = 27 = [Ar]3d7 4s2
⇒ M2+ = [Ar]3d7
Hence, 3 unpaired electrons are present.
The spin only magnetic moment μ= √n(n+2)
Where n is the number of unpaired electrons.
Hence, μ =√(3×(3+2))
μ = √15 BM or μ = 3.87 BM
Rate this question :