Answer :

Given, Z=atomic number = 27 = [Ar]3d7 4s2


M2+ = [Ar]3d7


Hence, 3 unpaired electrons are present.


The spin only magnetic moment μ= √n(n+2)


Where n is the number of unpaired electrons.


Hence, μ =√(3×(3+2))


μ = √15 BM or μ = 3.87 BM


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