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HC Verma - Concepts of Physics Part 2

46. The Nucleus

23. Heat and Temperature
24. Kinetic Theory of Gases
25. Calorimetry
26. Laws of Thermodynamics
27. Specific Heat Capacities of Gases
28. Heat Transfer
29. Electric Field and Potential
30. Gauss’s Law
31. Capacitors
32. Electric Current in Conductors
33. Thermal and Chemical effects of Electric Current
34. Magnetic Field
35. Magnetic Field due to a Current
36. Permanent Magnets
37. Magnetic Properties of Matter
38. Electromagnetic Induction
39. Alternating Current
40. Electromagnetic Waves
41. Electric Current through Gases
42. Photoelectric Effect and Wave-Particle Duality
43. Bohr’s Model and Physics of the Atom
44. X-rays
45. Semiconductors and Semiconductor Devices
46. The Nucleus
47. The Special Theory of Relativity

Short Answer

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Objective I

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Objective II

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Exercises

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Q. 525.0( 1 Vote )

Calculate the Q-value of the fusion reaction

⁴He + ⁴He = ⁸Be.

Is such a fusion energetically favorable? Atomic mass of ⁸Be is 8.0053 u and that of ⁴He is 4.0026 u.

Class 12th HC Verma - Concepts of Physics Part 2 46. The Nucleus

Answer :

⁴He + ⁴He = ⁸Be.

Q value= [2m(⁴He)- m(⁸Be)]u

= [2×4.0026 – 8.0053] × 931MeV

=-93.1KeV

Negative sign indicates that the energy has to be provided to proceed this reaction. So, this fusion is not favorable.

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PREVIOUSConsider the fusion in helium plasma. Find the temperature at which the average thermal energy 1.5 kT equals the Coulomb potential energy at 2 fm.NEXTCalculate the energy that can be obtained from 1 kg of water through the fusion reaction2H + 2H →3H + p.Assume that 1.5 × 10–2% of natural water is heavy water D2O (by number of molecules) and all the deuterium is used for fusion.

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HC Verma - Concepts of Physics Part 2