Q. 525.0( 1 Vote )

# Calculate the Q-value of the fusion reaction4He + 4He = 8Be.Is such a fusion energetically favorable? Atomic mass of 8Be is 8.0053 u and that of 4He is 4.0026 u.

4He + 4He = 8Be.

Q value= [2m(4He)- m(8Be)]u

= [2×4.0026 – 8.0053] × 931MeV

=-93.1KeV

Negative sign indicates that the energy has to be provided to proceed this reaction. So, this fusion is not favorable.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
The Embryonic Development62 mins
NCERT Exemplar Special | The Living World Part 225 mins
Nernst Equation - Learn the Concept33 mins
Understanding the Combination of cells54 mins
Revising the basics of Organic Chemistry35 mins
Types of solution on the basis of Raoult's Law44 mins
Nucleophilic Substitution Reaction | Getting the basics39 mins
Ray Optics | Getting the basics46 mins
Understant the concept of Development of pollen grains55 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

The binding energy of a H-atom, considering an electron moving around a fixed nuclei (proton), is . (m = electron mass). If one decides to work in a frame of reference where the electron is at rest, the proton would be moving around it. By similar arguments, the binding energy would be

(M = proton mass)

This last expression is not correct because

Physics - Exemplar