Q. 224.4( 9 Votes )

Calculate the num

Answer :

Given: At. Mass of AL = 27 u

Molar mass of aluminium oxide (Al2O3) = 2 × 27 + 3× 16 = 54 + 48 = 102g


This means 102g of Al2O3 has 2 × 6.022 × 1023 molecules


Then 0.051g contains:




Number of Al3+ ions = 6.022 × 1020


Thus, 0.051 g of aluminium oxide contains 6.022 × 1020 aluminium ions.


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