Answer :
We know
ΔT f= k f × m
Where ΔTf is the depression in the freezing point
Kf freezing constant for water
m is molality
The molality(m) of a given solution of glucose:
M=1.33 mol kg-1
Putting the values in the equation, we get
ΔTf= 1.86 × 1.33K
ΔT f= 2.4738K
ΔT f = T f × 2.4738K
Δt(solution) = t(solvent) – ΔTf
ΔT f= Tf0 2.4738K
= 273.15 - 2.4738K
= 270.65K
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