Answer :


At anode: [Oxidation]


At cathode: [Reduction]


Total electrons transferred (n) = 6.


Also, E°cell= E°cathode+ E°anode= -0.25V –(-1.66V) = 1.41 V


From Nernst equation, we know,


Ecell = E0cell – () [Coxid = concentration at the oxidation cell (0.001 M) and Cred = concentration at the reduction cell(0.1M)]


= 1.41 – ()


= 1.41 + 0.0295 = 1.4395V


So, the value of Ecellis 1.4395V.


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