At anode: [Oxidation]
At cathode: [Reduction]
Total electrons transferred (n) = 6.
Also, E°cell= E°cathode+ E°anode= -0.25V –(-1.66V) = 1.41 V
From Nernst equation, we know,
Ecell = E0cell – () [Coxid = concentration at the oxidation cell (0.001 M) and Cred = concentration at the reduction cell(0.1M)]
= 1.41 – ()
= 1.41 + 0.0295 = 1.4395V
So, the value of Ecellis 1.4395V.
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