Answer :

At anode: [Oxidation]

At cathode: [Reduction]

Total electrons transferred (n) = 6.

Also, E°cell= E°cathode+ E°anode= -0.25V –(-1.66V) = 1.41 V

From Nernst equation, we know,

Ecell = E0cell – () [Coxid = concentration at the oxidation cell (0.001 M) and Cred = concentration at the reduction cell(0.1M)]

= 1.41 – ()

= 1.41 + 0.0295 = 1.4395V

So, the value of Ecellis 1.4395V.

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Consider Fig. 3.2Chemistry - Exemplar

Consider Fig. 3.2Chemistry - Exemplar

Match the items oChemistry - Exemplar