Q. 123.6( 5 Votes )

# Calculate the ele

Answer :

8.5mVm^{-1}

Given,

Area of cross-section of wire, A=2.0 mm^{2}=2×10^{-6} m^{2}

Current flowing through the wire, I=1A

Resistivity of copper, ρ= 1.7 × 10^{–8} Ω m

Formula used,

From electrostatics, we know that Electric field, E is

Or it can be written as

Where l is the distance over which potential difference V has an effect

From Ohm’s law and the concept of current density, the relation connecting resistance, R and resistivity, ρ can be written as,

Where ‘l’ is the length of the conductor (or wire) and ‘A’ is the area of cross-section of the conductor.

Solution,

We know that potential difference, V is

Using eqn.2, the above expression can be modified as,

Now, in order to find the electric field by eqn.1, we can replace V in eqn.1 with the above expression as,

On simplification, it becomes,

We have all the values for the above expression. So, on substitution, Electric field will be,

Hence the electric field in a copper wire is 8.5mVm^{-1}

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