Q. 304.3( 12 Votes )
Calculate the amount of benzoic acid required for preparing 250mL of 0.15M solution in methanol.
Molarity = moles of the solute / volume of solution
Using the above formula we get,
0.15 = (mole of benzoic acid)/250 x 1000
moles of benzoic acid = (0.15 x 250)/1000
= 0.0375 mol of benzoic acid
Molecular mass of benzoic acid with the formula C6H5COOH
= 7 × 12 + 6 × 1 + 2 × 16
= 122 g/mol
Hence, amount of benzoic acid = 0.0375 x 122 = 4.575 g
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