Q. 16 A5.0( 3 Votes )

# <span lang="EN-US

Balanced equation: C6H12O6(s) 2C2H5OH(s) +2CO2(g)

Explanation:

Step 1: Write the given unbalanced equation

C6H12O6 C2H5OH+CO2

Step 2: Compare the number of atoms of reactants with the number of atoms of products.

Step 3: Now, first we consider the element having unequal no. of atoms on both sides. Thus, first let us consider hydrogen atom. If we multiply 2 in the product (in C2H5OH), we will get the equal number of atoms as in reactant (in C6H12O6)

Step 4: Write the resulting equation:

C6H12O6 2C2H5OH+CO2

Step 5: Now check whether the equation is balanced or not by comparing the atoms

We find that the equation is not balanced yet. As the number of carbon and oxygen atoms are unequal on the two sides.

First balance the carbon atom.

Step 6: If we multiply 2 in the product (in CO2), we will get the equal number of atoms as in reactant (in C6H12O6)

Step 7: Write the resulting equation:

C6H12O6 2C2H5OH+2CO2

Step 8: Now check whether the equation is balanced or not by comparing the atoms.

We find that the equation is balanced now.

Step 9: Write down the final balanced equation:

C6H12O6 2C2H5OH+2CO2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Knowledge Ride on Redox Reactions45 mins
Introduction to Linear Equations in Two Variables62 mins
Pair of Linear Equations-Yahaan se laye marks57 mins
Heights and Distances-I45 mins
Cube and Cuboid41 mins
History - Concept and Questions57 mins
Resources and Development Revision28 mins
Sphere and Hemisphere16 mins
Corrosion: Types, Pros and Cons41 mins
Right Circular Cylinder45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry

<span lang="EN-USAP - Physics & Chemistry