Q. 244.4( 13 Votes )
Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3CN, CH3OH.
Now n-octane is non-polar solvent due to long chain saturated structure. We know that “like dissolves like” so a non-polar compound will be more soluble in non-polar solvent as compared to polar compound.
So cyclohexane is non-polar due to symmetric structure. KCl is ionic in nature as it will dissociate into K + and Cl- ions. CH3CN is polar as mentioned above and CH3OH is also polar in nature.
The order of increasing polarity is:
Cyclohexane < CH3CN < CH3OH < KCl (O is more electronegative than N)
Therefore, the order of increasing solubility is:
KCl < CH3OH < CH3CN < Cyclohexane
Rate this question :
(a) A 10% solution (by mass) of sucrose in water has a freezing point of 269.15K. Calculate the freezing point of 10% glucose in water if the freezing point of pure water is 273.15 K.
(Molar mass of sucrose = 342 g mol–1)
(Molar mass of glucose = 180 g mol–1)
(b) Define the following terms :
(i) Molality (m)
(ii) Abnormal molar mass
(a) 30 g of urea (M = 60g mol–1) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.
(b) Write two differences between ideal solutions and non-ideal solutions.Chemistry - Board Papers
(i) Write the colligative property which is used to find the molecular mass of macromolecules.
(ii) In non-ideal solution, what type of deviation shows the formation of minimum boiling azeotropes?Chemistry - Board Papers
Explain the terms ideal and non-ideal solutions in the light of forces of interactions operating between molecules in liquid solutions.Chemistry - Exemplar
Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water?
(iii) formic acid
(iv) ethylene glycol
(vi) pentanolNCERT - Chemistry Part-I
Components of a binary mixture of two liquids A and B were being separated by distillation. After some time separation of components stopped and composition of vapour phase became same as that of liquid phase. Both the components started coming in the distillate. Explain why this happened.Chemistry - Exemplar