# Balance the follo

(a) Step 1 - To balance chemical equations, first list the number of atoms of different type that are present in the chemical equation on both sides -

HNO3 + Ca(OH)2→ Ca(NO3)2 + H2O Step 2 - To start balancing, we find the compound that has the highest number of atoms. We can see that Ca(NO3)on the product side has the highest number of atoms. In this compound Oxygen has the highest number of atoms. Lets start with that. This makes the partially balanced equation -

2HNO3 + Ca(OH)2→ Ca(NO3)2 + 2H2O

Step 3 - Now checking for all other elements we note that the number of atoms on both side are same. We can say that the equation is balanced.

(b)NaOH + H2SO4→ Na2SO4 + H2O
Step 1 - To balance chemical equations, first list the number of atoms of different type that are present in the chemical equation on both sides –

NaOH + H2SO4→ Na2SO4 + H2O Step 2 - To start balancing, we take any one compound. We will take NaOH on the reactant side in consideration. Let’s start with that. This makes the partially Balanced Equation as:-

2NaOH + H2SO4-> Na2SO4 + 2H2O

Step 3 - Now checking for all other elements we note that the numbers of atoms on both sides are same. We can say that the equation is balanced.

(c) NaCl + AgNO3→ AgCl + NaNO3

Step 1 - To balance chemical equations, first list the number of atoms of different type that are present in the chemical equation on both sides –

NaCl + AgNO3→ AgCl + NaNO3 We can see that the Number of Atoms in LHS and RHS are equal, Hence the equation is already balanced

(d) BaCl2 + H2SO4→ BaSO4 + 2HCL
Step 1 - To balance chemical equations, first list the number of atoms of different type that are present in the chemical equation on both sides –
BaCl2 + H2SO4→ BaSO4 + 2HCL We can see that the Number of Atoms in LHS and RHS is equal, Hence the equation is already balanced.

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