Answer :

Given:


Image distance, v = −d = −25 cm


Focal length, f = 10 cm


Object distance = u


When the image is formed at the near point or at the minimum distance of distinct vision, we get the maximum possible magnification.


Applying the lens formula we have:


…(1)


Where, f0 = focal length of the objective lens


v0 = Distance of image formation


u0 = Distance of object from objective


Putting values in the equation (1) we get,



u = -50/7


u = -7.14 cm


Hence, the lens should be kept 7.14 cm away in order to view the squares distinctly.


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