Q. 154.0( 26 Votes )

At 700 K, equilib

Answer :

For the reaction,

H2 (g) + I2 (g) 2HI (g)

Equilibrium constant is given to be 54.8.

i.e, Kc =

Let x be equilibrium concentration of H2 at equilibrium. Then equilibrium concentration of I2 will also be x. Since, initially there was only HI present, equal amount of H2 and I2 will be produced.

At equilibrium:

Kc =

= = 54.8

x =

= 0.0675

Therefore, concentration of H2 and I2 is 0.0675 mol L-1

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