Q. 17 B5.0( 1 Vote )

# At 300 K, 36 g of glucose, C_{6}H_{12}O_{6} present per litre in its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of another glucose solution is 1.52 bar at the same temperature, calculate the concentration of the other solution.

Answer :

Given:

Weight of Glucose, w = 36g

Osmotic Pressure of first glucose solution, n_{1} = 4.98 bars

Osmotic Pressure of second glucose solution, n_{2} = 1.52 bars

Concentration of first glucose solution, C_{1} = 36 / 180

= 1 / 5

= 0.2

To find: Concentration of the other solution, C_{2}:

Solution:

n = CRT

n_{1} = 0.2RT ………… (i)

4.98 = 0.2RT

RT = 24.9

n_{2} = C_{2} × RT

1.52 = C_{2} × 24.9

C_{2} = 1.52 / 24.9

C_{2} = 0.061 M

Therefore the concentration of the second solution of glucose is 0.061 M.

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