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Q. 35

Assuming the ideal diode, draw the output waveform for the circuit given in Fig. 14.17. Explain the waveform.

Class 12th Physics - Exemplar 14. Semiconductor Electronics

Answer :

The diode remains in forward bias till 20sinωt>5v. so, the circuit becomes,

Hence, we get a constant supply at the output. V₀=5V

As soon as 20sinωt < 5v happens, the diode goes into reverse bias state. So, the circuit becomes,

Hence we get the same output as per the input.

The waveforms look like

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PREVIOUSConsider the circuit arrangement shown in Fig 14.16 (a) for studying input and output characteristics of n-p-n transistor in CE configuration.Select the values of RB and RC for a transistor whose VBE = 0.7 V, so that the transistor is operating at point Q as shown in the characteristics shown in Fig. 14.16 (b).Given that the input impedance of the transistor is very small and VCC = VBB = 16 V, also find the voltage gain and power gain of circuit making appropriate assumptions.NEXTSuppose a ‘n’-type wafer is created by doping Si crystal having 5 × 1028 atoms/m3 with 1ppm concentration of As. On the surface 200 ppm Boron is added to create ‘P’ region in this wafer. Considering ni = 1.5 × 1016 m–3, (i) Calculate the densities of the charge carriers in the n & p regions. (ii) Comment which charge carriers would contribute largely for the reverse saturation current when diode is reverse biased.

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