Q. 13.8( 5 Votes )

# Assume that the m

Answer :

Given mass of nucleus(M) = Amp

We know that, (mass of proton)

where μ is the atomic mass unit , Radius of nucleus(R)  Volume(V)   Density(D)  = 3.0000688 × 1017 kg/m3

Specific gravity = 3.0000688 × 1014.

Hence, the density of matter in kg m–3 inside a nucleus is 3.0000688 × 1017 kg/m3 and its specific gravity is 3.0000688 × 1014.

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