Q. 194.1( 29 Votes )

Arrange the bonds in order of increasing ionic character in the molecules: LiF, K2O, N2, SO2, and ClF3.

Answer :

N2 < SO2 <CIF3 < K2O < LiF

Explanation: First, we have to find out the ionic character in each molecule. As we know that ionic character in a molecule depends upon the electronegativity difference between the atoms. The higher the electronegativity difference, higher will be the ionic character.


LiF = The electronegativity of Li is 0.98 and electronegativity of F are 3.98. Hence the electronegativity difference between Li—F atoms is 3


K2O = The electronegativity of K is 0.82 and the electronegativity of oxygen is 3.4. Hence the electronegativity difference between


K2—O atoms is 2.58


N2 = The electronegativity of N is 3.04. Hence the electronegativity difference between N—N atoms is 0


SO2 = The electronegativity of S is 2.58 and the electronegativity of oxygen is 3.4. Hence the electronegativity difference between


S—O2 atoms is 0.82


CIF3 = The electronegativity of F, I and C is 3.9, 2.6 and 2.5 respectively. Hence the electronegativity difference between


C—I—F3 atoms is 1.2


As 0 < 0.9 < 1.2 < 2.58 < 2.92


The ionic character increases with increase in the electronegativity difference.


N2 < SO2 <CIF3 < K2O < LiF


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