# Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions?

Given formula of nickel oxide = Ni0.98O1.00

Therefore, Ni:O = 0.98:1.00

Let the total no. of Ni ion = 98
and, the total no. of O ion = 100

So, Total charge on O-2 ion = 100 × (-2) = -200

Now, let the number of Ni2+ ions = x

Therefore, number of Ni+3 = 98- x

Now, since compound is neutral

Therefore, no. of Ni2+ ions + no. of Ni3+ ions +no. of O-2 ions = 0

x (+2) + (98 - x) × (+3) + (-200) = 0

+2x + 294 - 3x – 200 =0

x-94 = 0

x = 94

Therefore, the number of Ni2+ ions = 94

Number of ni3+ ions = 98- 94 = 4

Now, fraction of nickel exists as Ni2+ = 0.959

Fraction of nickel exists as Ni 3+ ions = 0.041

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