Q. 194.1( 23 Votes )
An organic compou
Answer :
C = 69.77% ie ==5.88;
H=11.63% ie==11.63;
O=(100-(69.77+11.63))=18.6% ie==1.16
Molecular Ratio will be 5.88:11.63:1.16=5:10:1.
Empirical formula is C5H10O, molecular weight will be =86.
Hence molecular formula will be same.
It does not reduce tollen’s reagent, it is not an aldehyde. The compound is addition product of sodium hydrogen sulphite it must be a ketone, It is giving positive iodoform test it is ethyl ketone. On vigorous oxidation, it forms ethanoic acid and propanoic acid the given compound is pentane-2-one.
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