An organic aromat
⇒ Since compound A (C6H7N) is sparingly soluble in water and gives a water soluble compound (B), on treatment with dilute acid, therefore, compound A must be an amine.
⇒ Since compound A reacts C6H7N reacs with NaNO2 and HCl to form a compound (E) which reacts with phenol in alkaline medium to give an orange red dye (F), therefore, compound (A) must be an aromatic primary amine, i.e., aniline C6H5NH2
⇒ If A is aniline, then E must be benzenediazonium chloride and the orange red dye (F) must be p-hydroxyazobenzene.
⇒ Since compound A aniline reacts with CHCl3 in the resence f alcoholic KOH o form a compound C having obnoxious smell, therefore, compound (C) must be benzene isonitrile.
⇒ Since compound (A) aniline reacts with benzenesulphonyl chloride to form compound (D) which is soluble in alkali, therefore (D) must be N- phenylbenzenesulphonamide.
⇒ Since compound (A) aniline reacts with mineral acid, HCl to form water soluble compound (B), therefore, (B) must be anilinium chloride.
Thus, compound A is aniline
Compound B is anilinium chloride
Compound C is benzene isonitrile
Compound D is N-phenylbenzenesulphonamide
Compound E is benezenediazonium chloride
Compound F is p-hydroxyazobenzene
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