Q. 153.9( 135 Votes )

An object of mass

Answer :

Given,

Mass of object, m1 = 1 kg


Velocity of object, v1= 10 m/s


Momentum of object = m1 × v1


= 1× 10 kg m/s


= 10 kg m/s (i)


Mass of wooden block, m2 = 5 kg


Velocity of wooden block, v2 = 0 (As it is stationary)


Momentum of wooden block = m2 × v2


= 5 × 0


= 0 kg m/s (ii)


From (i) and (ii), we get:


Total momentum = 10 + 0


Before impact = 10 kg m/s (iii)


Total momentum (after impact) =10 kg m/s[Law of conservation of momentum]


Total mass of object = 1 kg + 5 kg


= 6 kg


Velocity of object and wooden block = v m/s


10 = 6 × v


v =


v = 1.67 m/s


Therefore, the velocity of the object and wooden block together is 1.67 m/s.


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