Answer :

Given,

Mass of object, m_{1} = 1 kg

Velocity of object, v_{1}= 10 m/s

Momentum of object = m_{1} × v_{1}

= 1× 10 kg m/s

= 10 kg m/s (i)

Mass of wooden block, m_{2} = 5 kg

Velocity of wooden block, v_{2} = 0 (As it is stationary)

Momentum of wooden block = m_{2} × v_{2}

= 5 × 0

= 0 kg m/s (ii)

From (i) and (ii), we get:

Total momentum = 10 + 0

Before impact = 10 kg m/s (iii)

Total momentum (after impact) =10 kg m/s[Law of conservation of momentum]

Total mass of object = 1 kg + 5 kg

= 6 kg

Velocity of object and wooden block = *v* m/s

10 = 6 × *v*

v =

v = 1.67 m/s

Therefore, the velocity of the object and wooden block together is 1.67 m/s.

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