# An object of mass

Given,

Mass of object, m1 = 1 kg

Velocity of object, v1= 10 m/s

Momentum of object = m1 × v1

= 1× 10 kg m/s

= 10 kg m/s (i)

Mass of wooden block, m2 = 5 kg

Velocity of wooden block, v2 = 0 (As it is stationary)

Momentum of wooden block = m2 × v2

= 5 × 0

= 0 kg m/s (ii)

From (i) and (ii), we get:

Total momentum = 10 + 0

Before impact = 10 kg m/s (iii)

Total momentum (after impact) =10 kg m/s[Law of conservation of momentum]

Total mass of object = 1 kg + 5 kg

= 6 kg

Velocity of object and wooden block = v m/s

10 = 6 × v

v = v = 1.67 m/s

Therefore, the velocity of the object and wooden block together is 1.67 m/s.

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