Q. 163.5( 4 Votes )

An object of heig

Answer :

Given: Height of the object, h1 = 6 cm

Focal length of the concave mirror, f = -5 cm

Object distance, u = -10 cm

Applying the lens formula:

v= -3.3 cm

Now, as we know magnification is given by:

Equating both we get

h2=+2 cm

The image will be virtual, erect and diminished in size.

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