Answer :

According to the question;

Object distance (u) = - 10 cm;


Focal length (f) = 15 cm Image distance = v cm;


Height of object = 5 cm


By Mirror Formula;



.




V = 6 cm.


Since image distance v is positive


Image is virtual and erect.


Magnification (m) =




v < u Magnification < 1 hence image is diminished.


A virtual, erect and diminished image of height 3 cm is formed 6 cm behind the mirror.


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