According to the question;
Object distance (u) = - 10 cm;
Focal length (f) = 15 cm Image distance = v cm;
Height of object = 5 cm
By Mirror Formula;
⇒ V = 6 cm.
Since image distance v is positive
⇒ Image is virtual and erect.
Magnification (m) =
∵ v < u ⇒ Magnification < 1 hence image is diminished.
A virtual, erect and diminished image of height 3 cm is formed 6 cm behind the mirror.
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