Q. 194.8( 6 Votes )

# An object 2 cm in size is placed 30cm in front of a concave mirror of focal length 15cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? What will be the nature and the size of the image formed? Draw a ray diagram to show the formation of the image in this case.

Answer :

According to the question;

Object distance (u) = -30cm;

Focal length (f) = -15cm;

Image distance = v;

By mirror formula;

v = 30cm.

Thus, screen should be placed 30cm in front of the mirror (Centre of curvature) to obtain the real image.

Height of object h1= 2cm;

Magnification = =

Putting values of v and u

Magnification =

Height of image is 2 cm.

Negative sign means image is inverted.

Thus real, inverted image of size same as that of object is formed.

Diagram below shows the image formation.

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