Q. 433.7( 28 Votes )

An ion with mass

Answer :

Given:

Mass Number = 37


Percentage of neutron = 11.1% more as compared electrons


Let Number of electrons = number of protons = p


Let number of protons = p


Let number of neutrons= n


p + n = 81


p + {p + [11.1× p] / 100} = 37


p + 1.111p = 37


2.111p = 37


p = 37 / 2.111


p = 17.527


p = 17


Atomic Number = 17


The element is chlorine.


The atomic symbol is 3717Cl.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Give the number oNCERT - Chemistry Part-I

A certain particlNCERT - Chemistry Part-I

An ion with mass NCERT - Chemistry Part-I

An ion with mass NCERT - Chemistry Part-I

An element with mNCERT - Chemistry Part-I

In Milikan’s expeNCERT - Chemistry Part-I

Write the completNCERT - Chemistry Part-I

(i) Calculate theNCERT - Chemistry Part-I

How many neutronsNCERT - Chemistry Part-I

(i) Calculate theNCERT - Chemistry Part-I