Q. 175.0( 2 Votes )
An inductor-coil,
Answer :
Given that rms voltage 
=24V
Internal resistance, r= 4 ohm
Rms current 
=6A
Then, rms resistance will be
If this inductor coil is connected to a battery of emf E= 12 V and internal resistance r’ = 4.0Ω, then the steady current will be
Since, net resistance R’ = (R + r’) = 4+4 =8 ohm.
Therefore, the steady current (I) is
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